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Respond to the question: the gladiator game enigma?

 10/24/2010 10:25 PM by Roofing Contractors Austin; Home Improvement

 07/18/2010 04:12 PM by Roger; Where does the # come into it?

 06/06/2010 08:55 AM by Pinchas B; Can't Understand...
I am ashamed to admit that I don't understand how did you get the first line u the equation: W#(p+1) = (x/x+y)(W#(p)+Sy) + (y/x+y)(W#(p)-Sx) Will you be kind enough to go into details? Many thanks, Pinchas [View full text and thread]

 06/05/2010 03:13 PM by Emma; Hi
Hi. Can you explain me and simplify the equation and variables and how you solve that? [View full text and thread]

 06/04/2010 09:15 PM by skzap;
p is the total number of gladiators
S total strength of the field (and therefore constant)
T# total strength of team #
W# winning chances of team #

for p=2
W#(p) = T#/S

lets admit W#(p) = T#/S for any p,
therefore for p+1:
team # sends gladiator of strength x and other team of strength y

W#(p+1) = (x/x+y)(W#(p)+Sy) + (y/x+y)(W#(p)-Sx)
W#(p+1) = (xW#(p)+yW#(p)) / x+y
W#(p+1) = W#(p)

So ... winning chances of a team is proportional to their total number of strength.

Now just a basic ev prooves that order doesn't matter.

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 06/01/2010 04:29 PM by Emma; the gladiator game enigma
The game: There are two gladiators groups. Group A and Group B. Let assume that group A have 20 gladiators and group B have 30 gladiators. Every gladiator have a mark that represent his power in positive integer - 100, 140, 200, 80, [View full text and thread]